Solution
= Solution
There are $53$ observations. The null model estimates one intercept, so its residual degrees of freedom are $53-1=52$. The fitted model estimates three coefficients, so its residual degrees of freedom are $53-3=50$.
= Solution
There are $53$ observations. The null model estimates one intercept, so its residual degrees of freedom are $53-1=52$. The fitted model estimates three coefficients, so its residual degrees of freedom are $53-3=50$.