Solution
= Solution
For $b=(2,b,0)^T$, compatibility gives $b=-3$ when $a=-2$ and $b=2$ when $a=3$. The respective solution families are
$$
x=(1,-1,0)^T+t(1,1,1)^T
$$
and
$$
x=(1,-1,0)^T+t(-3/2,7/2,1)^T,
$$
where $t\in\mathbb R$.
= Solution
For $b=(2,b,0)^T$, compatibility gives $b=-3$ when $a=-2$ and $b=2$ when $a=3$. The respective solution families are
$$
x=(1,-1,0)^T+t(1,1,1)^T
$$
and
$$
x=(1,-1,0)^T+t(-3/2,7/2,1)^T,
$$
where $t\in\mathbb R$.