Solution
= Solution
With $\chi_A(t)=\det(tI-A)$, direct expansion gives
$$
\chi_A(t)=(t-3)(t-1)^2(t+1)(t+2).
$$
\b[Thus the <eigenvalues> are $3,1,-1,-2$. Kernel calculation gives <eigenspace> dimensions $1,2,1,1$, respectively.]
= Solution
With $\chi_A(t)=\det(tI-A)$, direct expansion gives
$$
\chi_A(t)=(t-3)(t-1)^2(t+1)(t+2).
$$
\b[Thus the <eigenvalues> are $3,1,-1,-2$. Kernel calculation gives <eigenspace> dimensions $1,2,1,1$, respectively.]