Solution
= Solution
Here the area factor is $\sqrt{1+2^2+3^2}=\sqrt{14}$ and the triangular base has area $3$. The surface area is therefore $3\sqrt{14}$.
= Solution
Here the area factor is $\sqrt{1+2^2+3^2}=\sqrt{14}$ and the triangular base has area $3$. The surface area is therefore $3\sqrt{14}$.