Solution
= Solution
For $\alpha=1$, the invariant of the characteristic equations is $z=xy$, so an invariant solution has $u(x,y)=f(z)$. Then
$$
u_{xy}=f'(z)+zf''(z).
$$
The invariant solutions are therefore characterized by
$$
\boxed{zf''+f'=e^f-e^{-2f}}.
$$