Solution
= Solution
Apply a <Hadamard gate> to Alice's qubit, followed by a <controlled-NOT gate> from Alice to Bob and another from Alice to Charlie:
$$
|000\rangle
\longmapsto
\frac{|000\rangle+|100\rangle}{\sqrt2}
\longmapsto
\frac{|000\rangle+|110\rangle}{\sqrt2}
\longmapsto
\frac{|000\rangle+|111\rangle}{\sqrt2}.
$$
\b[Thus this circuit gives the required <quantum circuit preparation of a three-qubit GHZ state>.]