Solution (source code)

= Solution

The first fit is a <Poisson regression> with independent responses
$$
Y_i\sim\operatorname{Poisson}(\mu_i),
\qquad
\log\mu_i=\beta_0+\beta_1x_{i1}+\beta_2x_{i2}.
$$
The fitted intercept gives $e^{3.8879}$ expected visitors when spending on both services is zero. Holding advert2 fixed, increasing advert1 by one unit, namely one hundred pounds, multiplies the expected visitor count by $e^{0.1923}\simeq1.212$.