Solution
= Solution
Yes. Every path from $D$ to $G$ is blocked by a collider, such as $D\to A\leftarrow G$ or $D\to C\to M\leftarrow A\leftarrow G$. Thus <D-separation> gives $D\mathbin\perp G$.
= Solution
Yes. Every path from $D$ to $G$ is blocked by a collider, such as $D\to A\leftarrow G$ or $D\to C\to M\leftarrow A\leftarrow G$. Thus <D-separation> gives $D\mathbin\perp G$.