= Solution
Let $c_s^2\sim P_g/\rho$. The assumed magnetic pressure gives
$$
\frac{P_m}{P_g}\sim\frac{\rho r\Omega c_s}{\rho c_s^2}
=\frac{r\Omega}{c_s}=\mathrm{Ma},
$$
so the <plasma beta> obeys $\boxed{\beta=P_g/P_m\sim\mathrm{Ma}^{-1}}$. In the magnetically dominated regime, vertical <hydrostatic equilibrium> gives $P_m/\rho\sim\Omega^2H^2$. Combining this with $P_m/\rho\sim r\Omega c_s$ yields
$$
\boxed{\frac Hr\sim\left(\frac{c_s}{r\Omega}\right)^{1/2}
\sim\mathrm{Ma}^{-1/2}}.
$$
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