Solution
= Solution
Since $1+i=\sqrt2e^{i\pi/4}$, the principal value is $\tfrac12\log2+i\pi/4$. All values are $\tfrac12\log2+i(\pi/4+2\pi k)$, $k\in\mathbb Z$.
= Solution
Since $1+i=\sqrt2e^{i\pi/4}$, the principal value is $\tfrac12\log2+i\pi/4$. All values are $\tfrac12\log2+i(\pi/4+2\pi k)$, $k\in\mathbb Z$.