Solution
= Solution
$e^x$ is real analytic because $e^{x_0+h}=e^{x_0}\sum_{n\ge0}h^n/n!$; it is not a <polynomial> since all its <derivatives> are nonzero.
= Solution
$e^x$ is real analytic because $e^{x_0+h}=e^{x_0}\sum_{n\ge0}h^n/n!$; it is not a <polynomial> since all its <derivatives> are nonzero.