Solution
= Solution
$ae+b/e$ is transcendental, hence irrational. If it were algebraic, $e$ would solve $ax^2-(ae+b/e)x+b=0$ over the algebraic numbers, contradicting transcendence of $e$.
= Solution
$ae+b/e$ is transcendental, hence irrational. If it were algebraic, $e$ would solve $ax^2-(ae+b/e)x+b=0$ over the algebraic numbers, contradicting transcendence of $e$.