Solution
= Solution
At $x=1$, direct substitution gives a product of odd half-integers. Taking logarithms and applying the hinted lower Riemann-sum estimate yields $\log\Pi(1)\gt n\log(2/e)$, hence $\Pi(1)\gt (2/e)^n$.
= Solution
At $x=1$, direct substitution gives a product of odd half-integers. Taking logarithms and applying the hinted lower Riemann-sum estimate yields $\log\Pi(1)\gt n\log(2/e)$, hence $\Pi(1)\gt (2/e)^n$.