Solution
= Solution
The dispersion relation is $\omega=ck$. At a perfect conductor the tangential <electric field> and normal <magnetic field> vanish. Thus $E_{ref}=-E_0\hat x e^{i(-kz+\omega t)}$ and $B_{ref}=-E_0\hat y e^{i(-kz+\omega t)}/c$. At the surface the <magnetic field> is $-2E_0\hat y/c$, so with outward normal $\hat z$ the surface current is $K=2E_0\hat x/(\mu_0c)$ (real parts understood).