Solution
= Solution
The transition <matrix> is symmetric with stationary projector $J/m$ and one other <eigenvalue> $\lambda=1-\alpha m/(m-1)$. Therefore, starting at BBC1, the probability of BBC2 after $60$ steps is $[1-\lambda^{60}]/m$.
= Solution
The transition <matrix> is symmetric with stationary projector $J/m$ and one other <eigenvalue> $\lambda=1-\alpha m/(m-1)$. Therefore, starting at BBC1, the probability of BBC2 after $60$ steps is $[1-\lambda^{60}]/m$.