Solution
= Solution
Approximate $g\in L^2$ by Schwartz $g_n$. Young's inequality gives
$\|f*(g_n-g)\|_2\le\|f\|_1\|g_n-g\|_2$, while multiplication by bounded $\widehat f$ is continuous in $L^2$. Pass to the <limit> in
$\widehat{f*g_n}=\widehat f\,\widehat g_n$.