Solution
= Solution
The saddle is $z_s=1+i$. Completing the square gives $\phi(z)=i-(z-1-i)^2/2$, so its steepest-descent line is the horizontal line $z=1+i+s$, $s\in\mathbb R$.
= Solution
The saddle is $z_s=1+i$. Completing the square gives $\phi(z)=i-(z-1-i)^2/2$, so its steepest-descent line is the horizontal line $z=1+i+s$, $s\in\mathbb R$.