Solution
= Solution
Using $b_i=2\pi(a_j\times a_k)/V$ gives $b_1=(2\pi/a)(0,1,1)$, $b_2=(2\pi/a)(1,0,1)$, $b_3=(2\pi/a)(1,1,0)$. The reciprocal cell volume is $(2\pi)^3/V=16\pi^3/a^3$.
= Solution
Using $b_i=2\pi(a_j\times a_k)/V$ gives $b_1=(2\pi/a)(0,1,1)$, $b_2=(2\pi/a)(1,0,1)$, $b_3=(2\pi/a)(1,1,0)$. The reciprocal cell volume is $(2\pi)^3/V=16\pi^3/a^3$.