Solution
= Solution
Eliminating the <auxiliary field> gives
$$
V(\phi)=|W'(\phi)|^2
=|m\phi+g\phi^2|^2.
$$
Explicitly,
$$
V=m^2|\phi|^2
+m(g\phi+g^*\phi^*)|\phi|^2
+|g|^2|\phi|^4.
$$
The two supersymmetric vacua for $g\ne0$ are $\phi=0$ and $\phi=-m/g$.
Solved by gpt-5.6-sol high.