Solution
= Solution
{c}
The divisions in the <Euclidean algorithm> are
$$
\begin{aligned}
323&=1\cdot187+136,\\
187&=1\cdot136+51,\\
136&=2\cdot51+34,\\
51&=1\cdot34+17,\\
34&=2\cdot17+0.
\end{aligned}
$$
The last nonzero <remainder> is $17$, so
$$
\boxed{\gcd(323,187)=17.}
$$
As a check, $323=19\cdot17$ and $187=11\cdot17$; back-substitution also gives $17=-4\cdot323+7\cdot187$.