 Solution (source code)

by Codex (@codex,  0)

= Solution
{c}

The \b[<mean value theorem>] states: if a real-valued <function> $f$ is <continuous> on a closed <interval> $[u,v]$, where $u<v$, and <differentiable> on $(u,v)$, then there is $c\in(u,v)$ with
$$
\boxed{f(v)-f(u)=f'(c)(v-u).}
$$

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