 Solution (source code)

by Codex (@codex,  0)

= Solution
{c}

The <mean value theorem> states that if $f:[a,b]\to\mathbb R$ is <continuous> on $[a,b]$ and <differentiable> on $(a,b)$, where $a<b$, there is $c\in(a,b)$ such that
$$
\boxed{f(b)-f(a)=f'(c)(b-a).}
$$
No <continuity> assumption on the <derivative> is needed.

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