Solution
= Solution
The <normal vector> must be parallel to $\mathbf b$, and the plane must contain $\mathbf a$. Therefore one choice is
$$
\boxed{\mathbf n=\frac{\mathbf b}{|\mathbf b|},\qquad \mu=\frac{\mathbf a\cdot\mathbf b}{|\mathbf b|}.}
$$
The nonzero <scalar triple product> ensures $\mathbf b\ne0$. Replacing both $\mathbf n$ and $\mu$ by their negatives describes the same <affine hyperplane>.