Solution
= Solution
The <exponential function> definitions of the <hyperbolic functions> and <Euler's formula> give
$$
\sinh(ix)=\frac{e^{ix}-e^{-ix}}2=i\sin x,\qquad\cosh(ix)=\frac{e^{ix}+e^{-ix}}2=\cos x.
$$
Dividing these identities wherever $\cos x\ne0$ gives $\boxed{\tanh(ix)=i\tan x}$. The two undivided identities hold for every <complex number> $x$; the quotient identity excludes its poles.