Solution
= Solution
The elementary bound $|\sin t|\leq|t|$ gives $0\leq\sin^2(1/n)\leq1/n^2$. Comparison with a convergent <p-series> proves \b[the series converges].
= Solution
The elementary bound $|\sin t|\leq|t|$ gives $0\leq\sin^2(1/n)\leq1/n^2$. Comparison with a convergent <p-series> proves \b[the series converges].