Solution
= Solution
Substituting into the fitted <factorial> logarithm gives
$$
\boxed{\ln(500!)\approx L(500)\simeq2611.3224.}
$$
This is an estimate from the requested two-point fit, not an exact factorial evaluation.
= Solution
Substituting into the fitted <factorial> logarithm gives
$$
\boxed{\ln(500!)\approx L(500)\simeq2611.3224.}
$$
This is an estimate from the requested two-point fit, not an exact factorial evaluation.