Solution
= Solution
Since $(1-i)^2=-2i$, division in the <complex numbers> gives
$$
\boxed{\frac{2+i}{(1-i)^2}=\frac{i(2+i)}2=-\frac12+i.}
$$
= Solution
Since $(1-i)^2=-2i$, division in the <complex numbers> gives
$$
\boxed{\frac{2+i}{(1-i)^2}=\frac{i(2+i)}2=-\frac12+i.}
$$