Solution
= Solution
For $p=3/4$, the five <probabilities> in increasing white-egg order are $(1,12,54,108,81)/256$. The largest is $108/256=27/64$, so the \b[most common nest has three white eggs and one brown egg], $W_3B_1$.
= Solution
For $p=3/4$, the five <probabilities> in increasing white-egg order are $(1,12,54,108,81)/256$. The largest is $108/256=27/64$, so the \b[most common nest has three white eggs and one brown egg], $W_3B_1$.