Solution
= Solution
<Completing the square> puts the equation of the <circle> in the form
$$
x^2+(y+3)^2=4.
$$
Hence its \b[centre is $(0,-3)$] and its <radius> is \b[$2$].
= Solution
<Completing the square> puts the equation of the <circle> in the form
$$
x^2+(y+3)^2=4.
$$
Hence its \b[centre is $(0,-3)$] and its <radius> is \b[$2$].