Solution
= Solution
This <arithmetic series> has $101$ terms, from $1$ to $201$. Thus
$$
\boxed{\sum_{n=0}^{100}(2n+1)=\frac{101(1+201)}2=101^2=10201.}
$$
= Solution
This <arithmetic series> has $101$ terms, from $1$ to $201$. Thus
$$
\boxed{\sum_{n=0}^{100}(2n+1)=\frac{101(1+201)}2=101^2=10201.}
$$