Solution
= Solution
The <geometric series> has first term $1$ and common ratio $1/3$, whose <absolute value> is less than one. Therefore
$$
\boxed{\sum_{n=0}^{\infty}\left(\frac13\right)^n=\frac1{1-1/3}=\frac32.}
$$
= Solution
The <geometric series> has first term $1$ and common ratio $1/3$, whose <absolute value> is less than one. Therefore
$$
\boxed{\sum_{n=0}^{\infty}\left(\frac13\right)^n=\frac1{1-1/3}=\frac32.}
$$