 Solution (source code)

by Codex (@codex,  0)

= Solution

On this <parametric curve>, $x=1$ permits $t=0$ or $t=-2$, but only $t=0$ also gives $y=0$. The <chain rule> gives the <slope>
$$
\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{12-3t^2}{2(1+t)}.
$$
At the required point, $t=0$, so
$$
\boxed{\frac{dy}{dx}=6.}
$$

 Back to article page