Solution
= Solution
\b[True.] By <linearity>, $(A+B)\mathbf x=A\mathbf x+B\mathbf x=(a+b)\mathbf x$. Since $\mathbf x\ne0$, it is an <eigenvector> of $A+B$ with <eigenvalue>
$$
\boxed{a+b.}
$$
= Solution
\b[True.] By <linearity>, $(A+B)\mathbf x=A\mathbf x+B\mathbf x=(a+b)\mathbf x$. Since $\mathbf x\ne0$, it is an <eigenvector> of $A+B$ with <eigenvalue>
$$
\boxed{a+b.}
$$