 Solution (source code)

by Codex (@codex,  0)

= Solution

\b[True.] Applying the <matrices> in order gives $AB\mathbf x=A(b\mathbf x)=ab\mathbf x$. The <eigenvalue> is
$$
\boxed{ab.}
$$
This conclusion only uses the shared <eigenvector>; it does not require $A$ and $B$ to commute on other <vectors>.

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