Solution
= Solution
Using $d(\sin^2x)/dx=2\sin x\cos x$, the <definite integral> is
$$
\boxed{J=\left[\frac12\sin^2x\right]_0^{\pi/2}=\frac12.}
$$
= Solution
Using $d(\sin^2x)/dx=2\sin x\cos x$, the <definite integral> is
$$
\boxed{J=\left[\frac12\sin^2x\right]_0^{\pi/2}=\frac12.}
$$