Solution
= Solution
Substituting $y=x/2$ into $xy=1$ gives $x^2=2$. The intersection points are $(\sqrt2,1/\sqrt2)$ and $(-\sqrt2,-1/\sqrt2)$. Their <Euclidean distance> is
$$
\boxed{\sqrt{(2\sqrt2)^2+(\sqrt2)^2}=\sqrt{10}.}
$$
= Solution
Substituting $y=x/2$ into $xy=1$ gives $x^2=2$. The intersection points are $(\sqrt2,1/\sqrt2)$ and $(-\sqrt2,-1/\sqrt2)$. Their <Euclidean distance> is
$$
\boxed{\sqrt{(2\sqrt2)^2+(\sqrt2)^2}=\sqrt{10}.}
$$