Solution
= Solution
Differentiate the numerator and denominator using the <product rule> and <quotient rule>:
$$
y'=\frac{(4x^3+3x^2)(3x-2)-12x^3(x+1)}{(3x-2)^5}.
$$
The numerator simplifies to $-11x^3-6x^2$, giving
$$
\boxed{y'=-\frac{x^2(11x+6)}{(3x-2)^5},\qquad x\ne\frac23.}
$$