Solution
= Solution
The <Maclaurin series> give $\sin(3x)=3x+O(x^3)$ and $\sinh x=x+O(x^3)$. Dividing by $x$ in a punctured neighborhood of zero gives
$$
\boxed{\lim_{x\to0}\frac{\sin(3x)}{\sinh x}=3.}
$$
= Solution
The <Maclaurin series> give $\sin(3x)=3x+O(x^3)$ and $\sinh x=x+O(x^3)$. Dividing by $x$ in a punctured neighborhood of zero gives
$$
\boxed{\lim_{x\to0}\frac{\sin(3x)}{\sinh x}=3.}
$$