Solution
= Solution
The <arithmetic series> formula, including both endpoints, gives
$$
\boxed{\sum_{n=0}^{100}(3n+2)=3\frac{100\cdot101}{2}+2\cdot101=15352.}
$$
= Solution
The <arithmetic series> formula, including both endpoints, gives
$$
\boxed{\sum_{n=0}^{100}(3n+2)=3\frac{100\cdot101}{2}+2\cdot101=15352.}
$$