Solution
= Solution
The <derivative> of the <hyperbolic sine> is the <hyperbolic cosine>. Hence the <chain rule> gives
$$
\boxed{\frac d{dx}\sinh^2x=2\sinh x\cosh x=\sinh2x.}
$$
= Solution
The <derivative> of the <hyperbolic sine> is the <hyperbolic cosine>. Hence the <chain rule> gives
$$
\boxed{\frac d{dx}\sinh^2x=2\sinh x\cosh x=\sinh2x.}
$$