Solution
= Solution
Use <completing the square> in each coordinate:
$$
(x-3)^2-9+(y-1)^2-1+1=0,
\qquad (x-3)^2+(y-1)^2=9.
$$
Comparing with the standard <circle> equation gives
$$
\boxed{\text{centre }(3,1),\qquad\text{radius }3.}
$$
= Solution
Use <completing the square> in each coordinate:
$$
(x-3)^2-9+(y-1)^2-1+1=0,
\qquad (x-3)^2+(y-1)^2=9.
$$
Comparing with the standard <circle> equation gives
$$
\boxed{\text{centre }(3,1),\qquad\text{radius }3.}
$$