Solution
= Solution
An <antiderivative> of $\sin x$ is $-\cos x$. The <fundamental theorem of calculus> gives
$$
\boxed{\int_0^{\pi/2}\sin x\,dx=[-\cos x]_0^{\pi/2}=1.}
$$
= Solution
An <antiderivative> of $\sin x$ is $-\cos x$. The <fundamental theorem of calculus> gives
$$
\boxed{\int_0^{\pi/2}\sin x\,dx=[-\cos x]_0^{\pi/2}=1.}
$$