Solution
= Solution
For the two-by-two <matrix>, take the product of the diagonal entries minus the product of the off-diagonal entries:
$$
\boxed{\det A=5\cdot5-(-3)(-3)=16.}
$$
In particular, $A$ is an <invertible matrix>.
= Solution
For the two-by-two <matrix>, take the product of the diagonal entries minus the product of the off-diagonal entries:
$$
\boxed{\det A=5\cdot5-(-3)(-3)=16.}
$$
In particular, $A$ is an <invertible matrix>.