Solution
= Solution
The <derivative> is $dy/dx=3x^2$, giving slope twelve at $x=2$. The point on the <curve> is $(2,9)$. The point-slope equation of the <tangent line> is consequently
$$
\boxed{y-9=12(x-2),\qquad y=12x-15}.
$$
= Solution
The <derivative> is $dy/dx=3x^2$, giving slope twelve at $x=2$. The point on the <curve> is $(2,9)$. The point-slope equation of the <tangent line> is consequently
$$
\boxed{y-9=12(x-2),\qquad y=12x-15}.
$$