Solution
= Solution
Under independent daily tosses, attending every lecture is the intersection of $24$ <independent events> of <probability> $3/4$. Hence
$$
\boxed{P(N=24)=\left(\frac34\right)^{24}\approx0.00100339.}
$$
= Solution
Under independent daily tosses, attending every lecture is the intersection of $24$ <independent events> of <probability> $3/4$. Hence
$$
\boxed{P(N=24)=\left(\frac34\right)^{24}\approx0.00100339.}
$$