 Solution (source code)

by Codex (@codex,  0)

= Solution

Multiply numerator and denominator by the <complex conjugate> of the denominator:
$$
\frac{2-3i}{2+3i}=\frac{(2-3i)^2}{2^2+3^2}
=-\frac5{13}-\frac{12}{13}i.
$$
Thus the <real part> and <imaginary part> are $\boxed{\operatorname{Re}=-5/13,\qquad\operatorname{Im}=-12/13}$.

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