Solution
= Solution
Write the rational expression as $(x^2+4)^{-1}$ and apply the <chain rule>:
$$
\boxed{\frac d{dx}\frac1{x^2+4}=-\frac{2x}{(x^2+4)^2}.}
$$
The denominator is positive for every real $x$, so the <derivative> is defined throughout the real line.