Solution
= Solution
The sum-of-cubes <polynomial factorization> is
$$
\boxed{a^3+b^3=(a+b)(a^2-ab+b^2).}
$$
Multiplication cancels the two mixed cubic terms and leaves precisely the two cubes.
= Solution
The sum-of-cubes <polynomial factorization> is
$$
\boxed{a^3+b^3=(a+b)(a^2-ab+b^2).}
$$
Multiplication cancels the two mixed cubic terms and leaves precisely the two cubes.