Solution
= Solution
Compute the first two moments from the <probability distribution>:
$$
\mu=E[X]=\frac6{10}+\frac6{10}=\frac65,\qquad
E[X^2]=\frac6{10}+\frac{12}{10}=\frac95.
$$
The <variance> is $E[X^2]-E[X]^2=9/5-36/25=9/25$, so the <expected value> and <standard deviation> are
$$
\boxed{\mu=\frac65,\qquad\sigma=\frac35}.
$$