Solution
= Solution
A <tangent line> through $(1,1)$ with slope $-2/3$ has equation
$$
\boxed{y-1=-\frac23(x-1),\qquad 2x+3y=5.}
$$
= Solution
A <tangent line> through $(1,1)$ with slope $-2/3$ has equation
$$
\boxed{y-1=-\frac23(x-1),\qquad 2x+3y=5.}
$$